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0=4x^2+380x-6600
We move all terms to the left:
0-(4x^2+380x-6600)=0
We add all the numbers together, and all the variables
-(4x^2+380x-6600)=0
We get rid of parentheses
-4x^2-380x+6600=0
a = -4; b = -380; c = +6600;
Δ = b2-4ac
Δ = -3802-4·(-4)·6600
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{250000}=500$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-380)-500}{2*-4}=\frac{-120}{-8} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-380)+500}{2*-4}=\frac{880}{-8} =-110 $
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